std::ranges::take_view<V>::take_view
来自cppreference.com
take_view() requires std::default_initializable<V> = default; |
(1) | (C++20 起) |
constexpr take_view( V base, ranges::range_difference_t<V> count ); |
(2) | (C++20 起) |
构造 take_view
。
2) 以 std::move(base) 初始化底层视图并以
count
初始化计数。构造后 base()
返回 base
的副本而 size()
返回 count
与 ranges::size(base) 的较小者。参数
base | - | 底层视图 |
count | - | 要收取的元素数 |
示例
打印首 n
个质数,用埃拉托色尼筛法生成起始。
运行此代码
#include <bit> #include <bitset> #include <iomanip> #include <iostream> #include <limits> #include <ranges> constexpr unsigned clog2(auto x) // ~ ⌈ log₂(x) ⌉ { return std::numeric_limits<decltype(x)>::digits - std::countl_zero(x); } template <unsigned Primes> struct Sieve { bool operator()(int n) { if (n < 2) return false; if (n == 2) return true; if (n % 2 == 0 || bits.test(n / 2)) return false; for (int i{n}, j{3}, k{}; (k = i * j) < size; j += 2) bits.set(k / 2); return true; } static constexpr int prime_numbers = Primes; // a(n) ~= n*(log(n) + log(log(n))); static constexpr int size = Primes*(clog2(Primes) + clog2(clog2(Primes))); // 仅保留奇数; 0 意味着它是质数 private: std::bitset<size / 2 + 1> bits; }; int main() { Sieve<100> sieve{}; auto primes_gen = std::views::iota(1) | std::views::filter(sieve); auto primes = std::ranges::take_view{ primes_gen, sieve.prime_numbers }; for (int n{1}; auto prime : primes) { std::cout << prime << (n++ % 10 ? ' ' : '\n'); } std::cout << "\n" "sieve.prime_numbers: " << sieve.prime_numbers << "\n" "sieve.size: " << sieve.size << "\n" "sizeof(sieve): " << sizeof sieve << " bytes\n"; }
输出:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199 211 223 227 229 233 239 241 251 257 263 269 271 277 281 283 293 307 311 313 317 331 337 347 349 353 359 367 373 379 383 389 397 401 409 419 421 431 433 439 443 449 457 461 463 467 479 487 491 499 503 509 521 523 541 sieve.prime_numbers: 100 sieve.size: 1000 sizeof(sieve): 64 bytes